10 drops of an oleic acid solution of concentration 1/400cm^3 per cm^3 of alcohol are dropped on a water surface. the circular film thus produced has radius 10cm. find the molecular size of oleic acid, if the radius of each drop is 1.4mm .
Answers
Answer:
We know, the Shape of the one Drops is Spherical in shape.
Radius of the Drop = 1.4 mm.
= 0.14 cm.
∴ Volume of the Drop = (4/3)π r³
= (4/3) × (22/7) × (0.14)³
= (241472 × 10⁻⁶) ÷ 21
Volume of the 10 Drop of 1/400 cm³ Concentration/cm³
= Volume of 1 Drop × 10 × 1/400
= (241472 × 10⁻⁶) ÷ (21 × 400)
= (603.68 × 10⁻⁶) ÷ 21
= 603.68/21000000 cm³
Radius of the Circular Film = 10 cm.
∵ Area = π r²
= (22/7) × (10)²
= 2200/7 cm²
Now,
Molecular Size or Thickness = Volume of one drop/Area of the Film.
=
= (603.68 × 7) ÷ (21 × 10⁶ × 2200)
= (4225.76 × 10⁻⁸) ÷ 462
= 9.1467 × 10⁻⁸ cm
Thus, the the Thickness or the Molecular size of drop of Oliec Acid is 9.1467× 10⁻⁸ cm.
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