10 drops of an oleic acid solution of concentration 1 by 400 cm cube per centimetre cube alcohol are dropped on water surface the circular film does produced has radius 10 cm find the molecular size of oleic acid if the radius of each drop is 1.4 mm
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circular film : r =10cm n=no of drops, concentration=1/400 cm³,
t = nv/400A
Area(A) = πr^2×400
=π×(10)^2×400
A = 4×10^4 πcm²
Volume of ten drops =4/3πr³
=4/3π×(1.4)³×10 mm³ [r=1.4]
=4/3π×2.744×10 mm³
=4/3π×2744×10^-3×10 mm³
=4/3π×2744×10^-2 mm³
=10976/3π×10²×10^-3 cm³
nV =10976/3π×10^-5 cm³
Molecular size =nV/400A
=10976π×10^-5cm³/3/4×10^4πcm³
=10976π×10^-5cm³/3×1/4×10^4πcm³
=9.15×10^-9m it is approx ans
t = nv/400A
Area(A) = πr^2×400
=π×(10)^2×400
A = 4×10^4 πcm²
Volume of ten drops =4/3πr³
=4/3π×(1.4)³×10 mm³ [r=1.4]
=4/3π×2.744×10 mm³
=4/3π×2744×10^-3×10 mm³
=4/3π×2744×10^-2 mm³
=10976/3π×10²×10^-3 cm³
nV =10976/3π×10^-5 cm³
Molecular size =nV/400A
=10976π×10^-5cm³/3/4×10^4πcm³
=10976π×10^-5cm³/3×1/4×10^4πcm³
=9.15×10^-9m it is approx ans
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Answer:9.11*10 to the power - 7cm
Explanation:
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