10 drops of olive oil of radius 0.2mm is spread into a circular film of radius 14.6 cm on water Surface. Find the thickness of molecule of olive oil drops.
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Given:
No of olive drops = 10
Radius of olive drops, r = 0.2 mm = 0.02 cm
Radius of circular film on water, R = 14.6 cm
To Find:
The thickness (or height) of molecule of olive oil drops, i.e., H.
Calculations:
Volume of circular oil film = Volume of 10 olive oil drops
πR²H = 10 × 4/3 πr³
⇒ H = (40 r³)/(3 R²)
⇒ H = {40 × (0.02)³} / {3 × (14.6)²}
⇒ H = (40 × 8 × 10⁻⁶) / (3 × 213.16)
⇒ H = (32 × 10⁻⁴) / (639.48)
⇒ H = 0.05 × 10⁻⁴ cm
⇒ H = 5 × 10⁻⁵ mm
- So the thickness of the olive oil film on water will be 5 × 10⁻⁵ mm.
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