10(e-29)
+ 6(p-29
20(p-29)
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Answer:
(10p^3)-(6p^2)q+(24pq^2)-(8q^3)+(6p^2)-24pq+(4q^2)-20p-40q
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i am in 8th standard and i did it in my head ,its too easy
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This is correct answer
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