Question

10. Each of the two equal angles of a triangle is 10° more than 1/2 of the third angle. Find the angels of the triangle.​

Answer 1

Answer:

The angles of the triangle are 80°, 50° and 50°.

Step-by-step explanation:

Let one angle be 'x'

As there are two equal angles, let they be 'y'.

We know that the sum of all interior angles of the triangle add upto 180°,

=> x + y + y = 180°

=> x + 2y = 180°

=> 2y = 180 - x           ---- (i)

According to the given conditions,

y = 10 + $\frac{x}{2}$

=> 2y = 20 + x                 ---(ii)

Equating equation (i) and (ii), we get

180 - x = 20 + x

=> 160 = 2x

=> 80 = x

2y = 180 - 80 (from equation (i))

2y = 100

y = 50

Therefore, the angles of the triangle are 80°, 50° and 50°.