Question

10 F of electricity is passed through the solutions of
silver nitrate, copper sulphate and ferric chloride. The
amount of metal deposited at cathode in each case
respectively are
(a) Ag = 1080 g Cu = 3175 g Fe = 1867 g
(b) Ag = 108 g Cu = 31.75 g Fe = 18.67 g
(c) Ag = 1080 g Cu = 317.5 g Fe = 186.7 g
(d) Ag = 10.8 g Cu = 317.5 g Fe = 186.7 g​

Answer 1

Answer:

1. (a) Ag = 1080 g Cu = 3175 g Fe = 1867 g
2. (b) Ag = 108 g Cu = 31.75 g Fe = 18.67 g
3. (c) Ag = 1080 g Cu = 317.5 g Fe = 186.7 g
4. (d) Ag = 10.8 g Cu = 317.5 g Fe = 186.7 g​

Answer 2

Answer:

c is the correct answer

Explanation:

okay