(10) Factors of x2 - 23x + 120
Answers
Answer:
Step-by-step explanation:
Step by step solution :
Step 1 :
Trying to factor by splitting the middle term
1.1 Factoring x2-23x+120
The first term is, x2 its coefficient is 1 .
The middle term is, -23x its coefficient is -23 .
The last term, "the constant", is +120
Step-1 : Multiply the coefficient of the first term by the constant 1 • 120 = 120
Step-2 : Find two factors of 120 whose sum equals the coefficient of the middle term, which is -23 .
-120 + -1 = -121
-60 + -2 = -62
-40 + -3 = -43
-30 + -4 = -34
-24 + -5 = -29
-20 + -6 = -26
-15 + -8 = -23 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and -8
x2 - 15x - 8x - 120
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-15)
Add up the last 2 terms, pulling out common factors :
8 • (x-15)
Step-5 : Add up the four terms of step 4 :
(x-8) • (x-15)
Which is the desired factorization
Final result :
(x - 8) • (x - 15)
Answer:
(x-15)(x-8)
Step-by-step explanation:
Hope it helps you.
