Question

10. Find a Pythagorean triplet whose one membe
is 323.​

Answer 1

Answer:

323 is member of the pythagorean triplet:

26083025²=323²+26081.25²

Step-by-step explanation:

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Answer 2

ANSWER

The required Pythagoras triplet is 323, 36 and 325

EXPLANATION

A Pythagorean triplet describes three sides over right triangle that holds integral value. i.e. they are integers.

A Pythagorean theorem can be written in the form: 2m, m² - 1 and m² + 1.

As 323 is an odd number, we won't get an integer that 'm', where 2m = 323.

So, Let's try with m² - 1

SOLUTION

⟹ m² - 1 = 323

⟹ m² = 323 + 1

⟹ m² = 324

⟹ m = √(324)

⟹ m = 18

The second number is 2m

⟹ 2m

⟹ 2(18)

⟹ 36

The third number is m² + 1

⟹ (18)² + 1

⟹ 324 + 1

⟹ 325

The required Pythagoras triplet is 323, 36 and 325

DOUBLE CHECK:

⟹ (2m²) + (m² - 1)² = (m² + 1 )

⟹ (36)² + (323)² = (325)²

⟹ 1,296 + 104,329 = 105625

⟹ 105625 = 105625

LHS = RHS