Question

10. Find a quadratic polynomial each with the given numbers as the sum and product of its zeros
respectively.
(I) -1/4, 1/4
(ii) √2, 1/3​

Answer 1

Step-by-step explanation:

${x}^{2} -(\alpha + \beta )x + \alpha \beta = 0$

(¡)x^2-(-1/4)x+(1/4)=0

→(4x^2+x+1)/4=0

→4x^2+x+1=0

(¡¡)x^2-(√2)x+(√2)(1/3)=0

→(3x^2-3√2x+√2)/3=0

→3x^2-3√2x+√2=0