Question

10. Find a quadratic polynomial whose zeroes are -9 and -1/9.​

Answer 1

Answer:

Hey mate here is ur answer↑

Polynomial=9x²-82x+9*[Mistake in Attachment]

Answer 2

Find a quadratic polynomial whose zeroes are -9 and -1/9

$9x^2 + 82x + 9 = 0$

Solution:

Given that,

Quadratic polynomial has zeros

$-9\ and\ \frac{-1}{9}$

Find the quadratic polynomial

The general form of quadratic polynomial is:

$x^2 - (sum\ of\ zeros)x + (product\ of \ zeros) = 0 --------- eqn\ 1$

Find sum of zeros:

$Sum\ of\ zeros = -9 - \frac{1}{9}\\\\Sum\ of\ zeros = \frac{-81 - 1}{9}\\\\Sum\ of\ zeros = \frac{-82}{9}$

Find product of zeros:

$Product\ of\ zeros = -9 \times \frac{-1}{9} = 1$

Form the quadratic polynomial:

By eqn 1,

$x^2 - (\frac{-82}{9})x + 1 = 0\\\\x^2 + \frac{82x}{9} + 9 = 0\\\\9x^2 + 82x + 9 = 0$

Thus the quadratic polynomial is found

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