Math, asked by oviyan91098, 4 months ago

10. Find a total number of ways in which one can wear 2 distinct rings R1 & R2 on
the five fingers of one's right hand, given that one is allowed to wear more than
one ring on a finger. *​

Answers

Answered by vonayvinay66
0

Answer:

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Answered by arshikhan8123
0

Concept:

The fundamental principle of counting: The total number of times that each event can occur is m n if one event can happen in m different ways and another in n different ways.

The basic tenet of counting only holds true when the decisions that must be made are made independently of one another.

A simple multiplication is ineffective if one alternative depends on another.

Given:

2 distinct rings R1 and R2

Find:

Find a total number of ways in which one can wear 2 distinct rings R1 & R2 on the five fingers of one's right hand, given that one is allowed to wear more than one ring on a finger.

Solution:

There are 5 different positions in which to position the first ring.

6 positions are possible for the second ring.

(5 rings + everything above or below the first ring)

Total no. of combinations =5 x 6

                                             = 30

Therefore.Total no. of combinations is 30

#SPJ2

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