Question

10. Find the angles of a triangle which are
in the ratio 4:3:2​

Answer 1

Given:

Angles of the triangle are in the ratio of 4:3:2.

To find:

The angles of the triangle.

Solution:

Let the first angle be 4x.

Let the second angle be 3x.

Let the third angle be 2x.

As we know that sum of all the angles of the triangle is 180°.

So,

4x + 3x + 2x = 180°

9x = 180°

$x = \dfrac{180}{9}$

$\bf \red{x = 20°}$

Verification:

On substituting the value of x as 20 in the equation,

4x + 3x + 2x = 180°

4×20°+3×20°+2×20° = 180°

80°+60°+40° = 180°

80°+100° = 180°

LHS = RHS

Hence Verified!

Final answer:

First angle of the triangle = 4x

= 4×20°

= 80°

Second angle of the triangle = 3x

= 3×20°

= 60°

Third angle of the triangle = 2x

= 2×20°

= 40°

Therefore the three angles of the triangle are 80°, 60° and 40°.

Answer 2

ANSWER =>

Given:

Angles of the triangle are in the ratio of 4:3:2.

To find:

The angles of the triangle.

Solution:

Let the first angle be 4x.

Let the second angle be 3x.

Let the third angle be 2x.

As we know that sum of all the angles of the triangle is 180°.

So,

4x + 3x + 2x = 180°

9x = 180°

x = \dfrac{180}{9}x=

9

180

\bf \red{x = 20°}x=20°

Verification:

On substituting the value of x as 20 in the equation,

4x + 3x + 2x = 180°

4×20°+3×20°+2×20° = 180°

80°+60°+40° = 180°

80°+100° = 180°

LHS = RHS

Hence Verified!

Final answer:

First angle of the triangle = 4x

= 4×20°

= 80°

Second angle of the triangle = 3x

= 3×20°

= 60°

Third angle of the triangle = 2x

= 2×20°

= 40°

Therefore the three angles of the triangle are 80°, 60° and 40°.

❤Sweetheart❤

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