Question

10) Find the area of the quadrilateral ABCD whose vertices are A(-3, -1), B(-2, -4),
C(4, – 1) and D(3, 4).​

Answer 1

Answer

just a second

Step-by-step explanation:

Given

quadrilateral ABCD

A(-3, -1),

B(-2, -4),

C(4, – 1)

and D(3, 4).

step 1 : find distance between two point

........by distance formula

d = √(x2-x1)²+(y2-y1)²

AB = √ (-2-[-3])²+(-4-[-1]²)

= √ (1)²+(-3)²

= √ 10

BC = √ (4-[-2])²+(-1-[-4])²

Answer 2

Step-by-step explanation:

The quadrilateral formed is rhombus...

so that we use area of rhombus =

d1 = length of diagonal 1. d2 = length of diagonal 2. b = length of any side. h = height of rhombus.