Math, asked by vijaymishra49, 1 year ago

10. Find the digit at the unit's
place of
(377)59 x (793)87 x (578)129 x
(99)99
(a) I (b) 2.
(c) 7
(d) 9​

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Answers

Answered by Anonymous
4

Answer:

It's too simple dear.... It's all about binomial theorem....

Let me send you the solution....

Wait.....

So I think (b) is the correct answer... Sorry for being late I thought it will not be easy to do it binomially as it can be hard to understand...

Simple trick is that whenever you multiply two numbers the last digit or unit place is simply the multiplication of last digits of given two numbers...

For example..

5892*2569 = 15136548...

Last digit is 8...

So for 5892 it's 2 at unit place... And for 2569 it is 9

So 2*9=18...and therefore last digit is 8....

Any doubts?....

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Answered by kothaarunaramkumar
3

Step-by-step explanation:

(377)59 × (793)87 × (578)129 × (99)99Number System l 31

6 5 4 3 2 1 1 2 3 4 5 60

Each point on the number line represents a unique real number and

each real number is denoted by a unique point on the number line.

Symbols of some special sets are:

N : the set of all natural numbers

Z : the set of all integers

Q : the set of all rational numbers

R : the set of all real numbers

Z+ : the set of positive integers

Q+ : the set of positive rational numbers, and

R+ : the set of positive real numbers

The symbols for the special sets given above will be referred

to throughout the text.

Even Integers

An integer divisible by 2 is called an even integer. Thus, ..., – 6, –

4, – 2, 0, 2, 4, 6, 8, 10, 12,...., etc. are all even integers. 2n always

represents an even number, where n is an integer.

For example, by putting n = 5 and 8 in 2n, we get even integer

2n as 10 and 16 respectively.

Odd Integers

An integer not divisible by 2 is called an odd integer.

Thus, ..., –5, –3, –1, 1, 3, 5, 7, 9, 11, 13, 15,..., etc. are all

odd integers.

(2n – 1) or (2n + 1) always represents an odd number, where

n is an integer.

For example by putting n = 0, 1 and 5 in (2n – 1), we get odd

integer (2n – 1) as – 1, 1 and 9 respectively.

Properties of Positive and Negative Numbers

If n is a natural number then

(A positive number)natural number = A positive number

(A negative number)even positive number = A positive number

(A negative number)odd positive number = A negative number

CONVERSION OF RATIONAL NUMBER OF

THE FORM NON-TERMINATING RECURRING

DECIMAL INTO THE RATIONAL NUMBER OF

THE FORM p

q

First write the non-terminating repeating decimal number in

recurring form i.e., write 64.20132132132.

................................ as 64 20132.

Then using formula given below we find the required p

q

form

of the given number.

Rational number in the form p

q

=

Complete number neglecting

the decimal and bar over

repeating digit( )

Non- recurring part of

the number neglecting

the decs

imal

m n times 9 followed by times 0

where m = number of recurring digits in decimal part

and n = number of non-recurring digits in decimals part

Thus, p

q

form of 64 20132. = 6420132 6420

99900

= 6413712

99900

534476

8325 =

In short; 0.a = , 0. , 0. , etc.

9 99 999

a ab abc ab abc = =and

0.ab = , 0. , 0. , 90 990 900

ab a abc a abc ab abc abc − − − = =

0. , 9900

abcd ab abcd − = , etc. 990

abcde abc ab cde − ⋅ =

Illustration 1: Convert 2 46102 . in the p

q

form of rational

number.

Solution: Required p

q

form =

246102 2

99999

246100

99999

− =

Illustration 2: Convert 0 1673206 . in the p

q

form of

rational number.

Solution: Required p

q

form =

1673206 167

9999000

1673039

9999000

− =

Illustration 3: Convert 31.026415555 ... into p

q

form of ra-

tional number.

Solution: First write 31.026415555... as 31 026415.

Now required p

q

form =

31026415 3102641

900000

27923774

900000

− =

= 13961887

450000 .

DIVISION

4 275 68

24

35

32

3

Here 4 is the divisor, 275 is the dividend,

68 is the

Remainder is always less than divisor.

quotient and 3 is the remainder.

Thus, Divisor Quotient Dividend

abc

Remainder

Thus,

Dividend = Divisor × Quotient + Remainder

For example, 275 = 4 × 68 + 3

When quotient is a whole number and remainder is zero, then

dividend is divisible by divisor.

TESTS OF DIVISIBILITY

I. Divisibility by 2:

A number is divisible by 2 if its unit digit is any of 0, 2,

4, 6, 8.

Ex. 58694 is divisible by 2, while 86945 is not divisible

by 2.

II. Divisible by 3:

A number is divisible by 3 only when the sum of its digits

is divisib

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