Question

10. Find the dimensions of (a xb) in the equation :
- x²
; where E is energy, x is distance and t is
time.
(Ans. M-'L?T)
E=
at
ant​

Answer 1

Explanation:

E = ( b -x²) /at

= ( b/at - x²/at)

where E = energy

t = time

x = displacement.

so,

dimension of E = dimension of { b/at }

b/at = E

b/a = Et

dimension of {a/b} = 1/Et = 1/[ ML²T-²][ T]

= [ M-¹ L-²T]