10. Find the greatest 4-digit number which is exactly divisible by 55, 88,110.
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Answer:
its 9999 it can be divisible by 55,88,110
Step-by-step explanation:
2 | 55 88 110
2 | 55 44 55
2 | 55 22 55
11 | 55 11 55
5 | 5 1 5
| 1 1 1
LCM(55,88,110)=2\times 2\times 2\times 11\times 5LCM(55,88,110)=2×2×2×11×5
LCM(55,88,110)=440LCM(55,88,110)=440
Divide 9999 by 440 so that we get the remainder,
9999 =440 \times 22+ 3199999=440×22+319
Remainder is 319.
Now, Subtract the remainder from 99999.
9999-319=96809999−319=9680
Therefore, The required number is 9680 which is exactly divisible by 55, 88 , 110
Hope it helps you
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