Question

10. Find the greatest number that divides 236, 276 and 305 leaving remainders 12, 10 and
respectively.
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Answer 1

Answer:

the answer is 14

Step-by-step explanation:gcd of 236 -12 ,276-10,305-11

gcd of 224 ,266,294

224=2×2×2×2×2×7

266=2×7×19

294=2×7x7x3

gcd is 14

the answer is 14.

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Answer 2

Answer:

The Brainliest Answer! One electron possesses a charge of 1.6 ×10-19C, i.e., 1.6 ×10-19C of charge is contained in 1 electron. Therefore, 6 x 1018 electrons constitute one coulomb of charge.Jul 29, 2017

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