Question

10. Find the greatest number that will divide 120, 160 and 145 leaving remainder 2 in each
case.​

Answer 1

Answer:

1

Step-by-step explanation:

120-2=118

160-2=158

145-2=143

Answer 2

The greatest number that will divide 120, 160 and 145 leaving remainder 2 in each case is 1.

Step-by-step explanation:

Given:

120, 160 and 145 leaving remainder 2 in each.

To Find:

The greatest number that will divide 120, 160 and 145 leaving remainder 2 in each case.

Solution:

As given-120, 160 and 145 leaving remainder 2 in each.

To make 120, 160 and 145 completely divisible by the greatest number, we need to subtract 2 from each term,

Therefore, 120-2=118,      160-2=158     and 145-2= 143.

Now HCF of 118, 158 and 143.

$118=1\times 2\times59$

$158=1\times 11\times13$

$143= 1\times2\times79$

Hence HCF of 118,158  and 143 is 1.

Thus,the greatest number that will divide 120, 160 and 145 leaving remainder 2 in each case is 1.

PROJECT CODE# SPJ2