Question

10.
Find the H.C.F of 4 x 27 x 3125, 8 X 9 X 25 X 7 and 16 x 81 x 5x114).​

Answer 1

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Answer 2

Answer:

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★Correct Question

• What is the HCF of 4 × 27 × 3125, 8 × 9 × 25 × 7 and 16 × 81 × 5 ×11 ×49?

★To find

• HCF

★Solution

»Finding factors of each

• 1st number = 2^2 x 3^3 x 5^5 x 7^0 x 11^0

• 2nd number = 2^3 x 3^2 x 5^2 x 7^1 x 11^0

• 3rd number = 2^4 x 3^4 x 5^1 x 7^2 x 11^1

»Then we take the lowest exponent for all the prime factors

»Then we take the lowest exponent for all the prime factorsThey are:

• 2^2

• 3^2

• 5^1

• 7^0 (note that for 7 and 11, the lowest exponent is 0 not 1)

• 11^0

»Multiply them all for the HCF

HCF = 2^2 x 3^2 x 5^1 x 7^0 x 11^0 = 4 x 9 x 5 x 1 x 1 = 180

★Hence required HCF is 180