Question

10. Find the HCF of the two numbers using the prime factors method,
(21.
48 and 60
Space for work
148 =
HCF =​

Answer 1

Answer:

$prime \: factors \: of \: 48 = 2 \times 2 \times 2 \times 2 \times 3 \\ prime \: factors \: of \:60 = 2 \times 2 \times 3 \times 5 \\ H. C. F= common factors \\ H. C. F = 2 \times 2 \times 3 \\ H. C. F = 12$

Answer 2

Answer:

prime factors of 48 = 2×2×2×2×3

prime factors of 60= 2×2×3×5 HCF = common factors HCF = 2×2×3 HCF=12

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