10. Find the least number which when divided by 35, 56 and 91 leaves the
same remainder 7 in each case
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Answer:
The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)
35=5×7
56=23×7
91=7×13
LCM=23×5×7×13=3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.
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