Question

10. Find the perimeter of a rectangle whose one side measures 10 m and the nagonal is 28
(a) 98 m
b) 68 m
(c) 80 cm​

Answer 1

Answer:

consider a rectangle ABCD then AB= 10m and one diagonal is 28m then BC^2= AC^2 - AB^2 (Pytagoras theorem)

BY SOLVING IT WE GET BC = 32.92m then perimeter = 2(l+b) =2(39.2+10)= 2(49.2) =2×49.2 =98.4m therefore perimeter of rectangle is 98.4m PLEASE MARK MY ANSWER AS BRAINLIST ANSWER