Question

10. Find the remainder in each of the following cases:
(0) When (2x4 - 6x3 + 2x2 - x + 2) is divided by
X + 1.
(ii) When 13x° -5x(x - 2) - V6(x² + 2) +
2/3(x+2) is divided by (x - 2).​

Answer 1

$\bold \red{answer}$

If x + 2 = 0

x = -2

f(x) = 2x4 – 6x3 + 2x2 – x + 2, [By remainder theorem]

f(x) = 2(-2)4 – 6(-2)3 + 2(- 2)2 – (- 2) + 2

= 2(16) – 6(- 8) + 2(4) + 2 + 2

= 32 + 48 + 8 + 2 + 2 = 92

Hence, required remainder = 92.