Math, asked by angrejgill948, 1 day ago

10. Find the smallest number which when divided by 15 and 18 leaves remainder
13.​

Answers

Answered by khushimondal1719
0

Answer:

6 = 2 × 3

15 = 3 × 5

18 = 2 × 3 × 3

L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5

L.C.M (6, 15 and 18) = 90

Therefore, the required number = 90+5 = 95

As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.

Answered by StarlightPhoenix
1

Answer:

103 is the correct answer .

103/15= 6 whole 15/13 .

103/18=5 whole 18/13

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