10. Find the smallest number which when divided by 15 and 18 leaves remainder
13.
Answers
Answered by
0
Answer:
6 = 2 × 3
15 = 3 × 5
18 = 2 × 3 × 3
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5
L.C.M (6, 15 and 18) = 90
Therefore, the required number = 90+5 = 95
As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.
Answered by
1
Answer:
103 is the correct answer .
103/15= 6 whole 15/13 .
103/18=5 whole 18/13
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