Math, asked by khushinpatel, 5 months ago

10. Find the smallest number which when divided
by any of the numbers 35, 56 and 91
leaves remainder 7 every time.​

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Answers

Answered by farhan3266
0

Answer:

to find the answer firstly we will find the LCM the LCM of 35 56 and 91 is 3640 and if we will add 7 to it then the answer is 3647 and when if we will divide this number from 35 56 and 91 then the reminder will be 7

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