Question

10. Find the value of 9 sec? A - 9 tan? A.​

Answer 1

Step-by-step explanation:

ANSWER

ANSWERWe have, 9sec

ANSWERWe have, 9sec 2

ANSWERWe have, 9sec 2 A−9tan

ANSWERWe have, 9sec 2 A−9tan 2

ANSWERWe have, 9sec 2 A−9tan 2 A

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 A

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)We know that

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)We know thatsec

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)We know thatsec 2

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)We know thatsec 2 A−tan

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)We know thatsec 2 A−tan 2

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)We know thatsec 2 A−tan 2 A=1

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)We know thatsec 2 A−tan 2 A=1Therefore,

ANSWERWe have, 9sec 2 A−9tan 2 ALet r=9sec 2 A−9tan 2 Ar=9(sec 2 A−tan 2 A)We know thatsec 2 A−tan 2 A=1Therefore,r=9×1=9

Answer 2

Answer:

The value of 9sec²A-9tan²A =9

Step-by-step explanation:

The value of 9sec²A-9tan²A

= 9(sec²A-tan²A)

/* By Trigonometric identity:

{sec^{2}A-tan^{2}A=1}

sec 2 A−tan 2 A=1

= 9 ×1

= 9