Question

10. Find the value of x for which (4/9)^4 × (4/9)^-7 = (4/9)^2x-1 .

please give answer ​

Answer 1

Answer:

VALUE OF X = (-1)

Step-by-step explanation:

(4/9)^4 * (4/9)^(-7) = (4/9)^2x-1

=> (4/9)^4+(-7) = (4/9)^2x-1

=> (4/9)^(-3) = (4/9)^2x-1

Since, The base on both sides is (4/9) or equal

Therefore, exponent of LHS = exponent of RHD

=> 2x-1 = (-3)

=> 2x = -3+1 = -2

=> x = (-1)

SO, THE VALUE OF "x" IS (-1)

Answer 2

Step-by-step explanation:

I hope this answer is right