Question

10. Find three consecutive numbers whose sum is 36.​

Answer 1

Answer:

Three consecutive integers whose sum is 36 are 11, 12, and 13. By definition, three consecutive integers take on the form n, n + 1, n + 2.

Answer 2

Answer:

11,12,13

Step-by-step explanation:

let the three consecutive no be x, x+1,x+2=36

add all the three x

3x+1+2 =36

3x+3=36

(take 3 to rhs)

3x=36-3

3x=33

(take 3 from LHS side to rhs side)

x=33/3(division)

x=11

1st consecutive no - x = 11

2nd consecutive no- x+1=11+1=12

3rd consecutive no - x+2 = 11+2 =13

so the three consecutive number are 11 ,12 and 13