Question

10. Find Time when
() Principal = Rs. 6000, S.I. = Rs. 1052 and Rate = 8% p.a.
(it) Principal = Rs. 4000,Amount = Rs. 5450 and Rate = 12% p.a.​

Answer 1

Answer:

Hope it helps you .......

mark as brainlist

Answer 2

➤ Given :-

Principle :- ₹ 6000

Simple Interest :- ₹ 1052

Rate of interest :- 8%

➤ To Find :-

Time of the first problem.............

➤ Formula required :-

$\large \dashrightarrow \orange{ \boxed{ \tt \gray{ \dfrac{SI \times 100}{P \times R} }}}$

➤ Solution :-

$\tt \longrightarrow \dfrac{1052 \times 100}{6000 \times 8}$

$\tt \longrightarrow \dfrac{1052 \times \cancel{100}}{ \cancel{6000} \times 8} = \dfrac{1052 \times 1}{60 \times 8}$

$\tt \longrightarrow \cancel \dfrac{1052}{480} = 2.1$

$\Huge\therefore$The time taken in the problem is 2.1 years.

━━━━━━━━━━━━━━━━━━━━━

➤ Given :-

Principle :- ₹ 4000

Amount :- 5450

Rate of interest :- 12%

➤ To Find :-

Simple Interest on the second problem........

➤ Formula required :-

$\large \dashrightarrow \orange{ \boxed{ \tt \gray{ \dfrac{SI \times 100}{P \times R } }}}$

➤ Solution :-

Simple Interest :-

$\tt \longrightarrow5450 - 4000$

$\longrightarrow \tt₹1450$

Now,

Time :-

$\tt \longrightarrow \dfrac{1450 \times 100}{4000 \times 12}$

$\tt \longrightarrow \dfrac{ \cancel{1450} \times 1}{ \cancel{40} \times 12} = \dfrac{1450 \times 1}{4 \times 12}$

$\tt \longrightarrow \cancel \dfrac{1450}{48} = 30.2$

$\Huge\therefore$The time taken in the problem is 30.2 years.

━━━━━━━━━━━━━━━━━━━━━

Some related formulas………

Simple Interest :- $\boxed{\tt P \times R \times T \div 100 }$

Principle :- $\boxed{\tt SI \times 100 \div R \times T}$

Rate of interest :- $\boxed{\tt SI \times 100 \div P \times T}$

━━━━━━━━━━━━━━━━━━━━━

More to know…………

• Principle is the money borrowed as loan in some bank, ATM or from a person.
• Rate of interest is the extra amount should be given at end of time given. It is usually written in percentage form.
• Time is given for the borrower to return the money with some interest given. It is usually written in days, months and years.