Question

10. Find two numbers such that one is 3 times the other and their difference
is 134.​

Answer 1

Given

• one is 3 times the other

• their difference is 134

To Find

• Two numbers

Solution :

Let, the no. be x

Their difference = 134

⇒ 3x - x = 134

⇒ 2x = 134

⇒ x = 134/2

⇒ x = 67

Value of 1st no. = x

→ Value of 1st no. = 67

Value of 2nd no. = 3x

→ Value of 2nd no. = 3 × 67

→ Value of 2nd no. = 201

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\:\:$

$\green{\underline \bold{Given :}}$

$\:\:$

• One number is 3 times the other

• Difference of the numbers is 134

$\:\:$

$\red{\underline \bold{To \: Find:}}$

$\:\:$

• The two numbers

$\:\:$

$\large{\orange{\underline{\tt{Solution :-}}}}$

$\:\:$

Let one number be 'x'

Let other number be 'y'

$\:\:$

$\purple{\underline \bold{According \: to \: the \ question :}}$

$\:\:$

$\purple\longrightarrow$ $\sf x = 3y$ ---------(1)

$\:\:$

$\underline{\bold{\texttt{Their difference :}}}$

$\:\:$

$\rm \longmapsto x - y = 134$ ------(2)

$\:\:$

$\underline{\bold{\texttt{Putting x = 3y in (2) }}}$

$\:\:$

$\sf \implies 3y - y = 134$

$\:\:$

$\sf \implies 2y = 134$

$\:\:$

$\sf \implies \boxed{y = 67}$

$\:\:$

So,

$\:\:$

x - 67 = 134

$\:\:$

$\sf \boxed {x = 201}$

$\:\:$

$\underline{\bold{\texttt{Hence the two numbers are:</p><p>}}}$

$\:\:$

• 201

• 67

$\rule{200}5$