10 Fiod The coefficient of x^12 in expansion of x^3(1-27)^10
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Answered by
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Step-by-step explanation:
(
2
x
−
x
2
3
)
10
T
r+1
=
10
C
r
(
2
x
)
10−r
(−
x
2
3
)
r
=
10
C
r
(
2
1
)
10−r
(−3)
r
(x
10−r
)(x
−2r
)
=
10
C
r
(
2
1
)
10−r
(−3)
r
[x
(10−r)+(−2r)
]
⇒(10−r)+(−2r)=4
⇒3r=6
⇒r=2
∴ Coefficent of x
4
=
10
C
2
(
2
1
)
10−2
(−3)
2
⇒
256
45×9
=
256
405
=
512
810
Hence the answer is
256
405
and
10
C
2
(
2
1
)
8
9
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