10. Five liters of air at -50.0˚C is warmed to 100.˚C. What is the new volume if the pressure remains constant?
Answers
Answered by
0
Given,
Volume 1 (V₁) = 5 L
Temperature 1 (T₁) = -50°C
= 273-50 K
= 223 K
Temperature 2 (T₂) = 100°C
= 273+100 K
= 373 K
By Charles's law,
V₁/T₁ = V₂/T₂
= 5/223 = V₂/373
= (373*5)/223 = V₂
= 8.36 L = V₂
The New Volume will be 8.36 L.
I hope this helps.
Similar questions