10. Five years ago, Nuri was thrice as old ae Sonu. Ten years later, Nuri will be twice as old as sonu.How old are Nuri and Sonu?
Answers
Let the present age of Nuri = x year
And present age of Sonu = y year
Five years ago
Age of Nuri = x – 5 years
Age of Sony = y – 5 years
Nuri was thrice as old as Sonu
X- 5 = 3(y – 5)
X – 5 = 35 – 15
X – 3y = -15 + 5
X – 3 y = - 10 ………..(1)
Ten years later,
Age of Nuri = x + 10
Age of Sonu = y + 10
Nuri will be twice as old as Sonu.
X+ 10 = 2(y+10)
X + 10 = 2y + 20
X – 2y = 10 ………..(2)
X – 3 y = - 10 ………..(1)
Subtracting equation (1) from equation (2) we get
Y = 20
Plug this value in equation first we get
X - 3* 20 = -10
X = 60 – 10
X = 50
Hence age of Nuri = 50 years and age of Sonu = 20 years
The age of Sonu is 20 years and Nuri is 50 years.
Given :
5 years ago = Nuri was thrice as old ae Sonu.
10 years later = Nuri will be twice as old as sonu
To find :
Ages of Nuri and Sonu
Solution :
Consider the age of Sonu as x
Consider the age of Nuri as y
The Ages 5 years ago =
Sonu = x - 5
Nuri = y - 5
Nuri was Thrice the age of Sonu (5 years before)
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10 years later :
Sonu's age = x + 10
Nuri's age = y + 10
Nuri will be twice as old as sonu.
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From Equation 1 and 2 =
Now, put the value of x in Equation 1
x = 20
y = 50
The age of Sonu is 20 years and Nuri is 50 years.