10. For
(0) A+B C: K=K,
(W)2CD: K = K,
Then the value of K, for 2D + A+B
5C will
(2) K
(4) KK
Answers
Answered by
9
Answer:
Difference of consecutive terms in an AP is constant.
so,
(3k+2)-(k+10)=(k+10)-2k
2k-8=-k+10
3k=18
k=6.
done.
:-)
pleasee follow:-)
Answered by
0
Answer:
Difference of consecutive terms in an AP is constant.
so,
(3k+2)-(k+10)=(k+10)-2k
2k-8=-k+10
3k=18
k=6.
done.
:-)
kk=6x6=36
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