Question

10)For a first order reaction, the time required for 99.9% completion is 100 min. What will be the rate constant for the reaction?

1.25 x 10-4 S-1

1.15 x 10-3 S-1

2.2 x 10-2 S-1

4.5 x 10-2 S-1​

Answer 1

Answer:

2nd is the correct answer

see the attachment

Explanation:

hope it will help you

Answer 2

1.15 x$10^{-3} s^{-1}$

For first order reaction,

the equation if as follows

K=$\frac{2.303}{t}log\frac{R_{0} }{R}$

Where K is the rate constant,

$R_{0}$ is the initial concentration of the reaction ,

R is the concentration of the reaction,

t is the time taken.

K=$\frac{2.303}{100}log\frac{100 }{0.1}$

K=$\frac{2.303}{100}log1000$

K=$\frac{2.303(3)}{100}$

K=6.909$10^{-2}$$min^{-1}$

K=6.909$10^{-2}$/60

K=1.15x$10^{-3} s^{-1}$.

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