Question

10) For an AP the first term is 5 and the common difference is 3 then the 15
th term of the AP is _______.

a)15 b) 30 c) 50 d) 47​

Answer 1

Answer:

Step-by-step explanation:

t  

n

​  

=a+(n−1)d where n = 11, a = 5, d = - 3

∴t  

11

​  

=5+(10)×(−3)=−25

Answer 2

Answer:

tn=a+(n−1)d where n = 11, a = 5, d = - 3

∴t15=5+(14)×(3)=47

ANSWER IS (D) .47