Question

10. For what value ofk,x = 2 satisfies 3x^ 2 -kx-2=0?​

Answer 1

Answer:

$= = > 3 {x}^{2} - kx - 2 = 0 \\ x = 2 \\ = = > 3( {2}^{2} ) - 2k - 2 = 0 \\ = = > \: \: 3(4) - 2k - 2 = 0 \\ = = > \: \: \: \: \: \: \: 12 - 2k - 2 = 0 \\ = = > \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 10 = 2k \\ = = > \: \: \: \: \: k = \frac{10}{2} = \frac{5}{1} = 5$

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Answer 2

p(x) = 3x² -kx-2=0

p(2) = 3(2)² -k(2)-2=0

p(2) =3×4 -2k -2 =0

12 -2k -2 =0

-2k = -10

k= 5