Question

10.From 8p2 - 11p - 50 take away 40 -2p2 + 7p​

Answer 1

$\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2-11p-50-\left(40-2p^2+7p\right)}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2-11p-50-40+2p^2-7p}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2+2p^2-11p-7p-50-40}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-11p-7p-50-40}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-18p-50-40}$

$\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-18p-90}$

Answer 2

Answer:

8p

2

−11p−50)−(40−2p

2

+7p)=8p

2

−11p−50−(40−2p

2

+7p)

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2-11p-50-40+2p^2-7p}⟶(8p

2

−11p−50)−(40−2p

2

+7p)=8p

2

−11p−50−40+2p

2

−7p

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=8p^2+2p^2-11p-7p-50-40}⟶(8p

2

−11p−50)−(40−2p

2

+7p)=8p

2

+2p

2

−11p−7p−50−40

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-11p-7p-50-40}⟶(8p

2

−11p−50)−(40−2p

2

+7p)=10p

2

−11p−7p−50−40

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-18p-50-40}⟶(8p

2

−11p−50)−(40−2p

2

+7p)=10p

2

−18p−50−40

\longrightarrow\rm{\left(8p^2-11p-50\right)-\left(40-2p^2+7p\right)=10p^2-18p-90}⟶(8p

2

−11p−50)−(40−2p

2

+7p)=10p

2

−18p−90