10 g Ag and 1 G s is used then how many grams of Ag2S will be formed ?
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16Ag + S8 => 8Ag2S
M.W of Ag = 108
M.W of S = 32
16*108 grams of Ag reacts completely with 32*8 grams of Sulphur
=> 1728g Ag reacts completely with 256g of S
=> 6.75g Ag reacts completely with 1g of S (By ratio proportion)
Thus, the remaining 3.25g will not react
=> Mass oh Ag2S formed = 6.75+1 = 7.75g
= 7.75g
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