Question

10 g CaCO₃ gives on strong heating CO₂. It gives quicklime
(in grams)
(a) 5g (b) 4.4 g (c) 5.6 g (d) 4 g

Answer 1

Answer:

Option c 5.6 is the answer

Answer 2

10 g CaCO₃ gives on strong heating 5.6 g of quicklime

Explanation:

Calcium carbonate on strong heating decomposes to give quicklime and carbon dioxide.

• $CaCO_3 \to CaO + CO_2$
• Molecular mass of $CaCO_3$ = 100 g
• Molecular mass of $CaO$ = 56
• From the equation, it is observed that 1 mole of $CaCO_3$ gives 1 mole of $CaO$ and 1 mole of $CO_2$.
• That is 100 g of $CaCO_3$ gives 56 g of $CaO$
• Then 10 g of $CaCO_3$ gives $CaO$
• $=\frac{10\times 56}{100} =5.6g$