Question

10 g fairly concentrated solution of CuSO4 is electrolysed by passing 10 ampere current for 1.5 minutes Calculate. a) the weight of resulting solution b) the number of equivalents of acid or alkali produced in solution (Cu 63.5)

Answer 1

Answer:

According to Faraday's First law:

W=ZQ

Z= electro chemical equivalent

W= weight of substance

Q= given 10 ampere current for 1.5 minutes

therefore,

Q= 10*1.5

   = 15 coulomb

   =0.000155 faraday

1 Faraday current deposits 63.5/2= 31.75 gm copper

0.000155 faraday current deposits = 31.75*0.000155

                                                              = 0.005 gm copper

solution weight initial 10 gm

after electrolysis weight of the solution 10-0.005= 9.995 gm

Equivalent of acid= charge= 0.000155