Question

10 g of a sample of conc. hydrochloric acid (HCI) solution diluted with water, was added to a
piece of marble (Cacog) weighing 7.0 g. After completion of the reaction,
2.8 g of marble remained unreacted. What was the percentage strength of the conc, acid ? [H = 1;
Cl = 35.5; Ca = 40 ; C = 12; 0 = 16).
(Ans. 30.66%]​

Answer 1

Answer:

30.66 percent

Explanation:

CACO3. + 2HCL. = CACL2 +H2O+CO2

(40+12+48)g. 2(1+35.5)

100g. 73g

MARBLE (CACO3). REACTED. = 7 - 2.8 = 4.2g

100g CACO3 REACTED = 73g HCL

4.2g. """""""""""""""''''''''''''''=. 3.066g

strength percentage= 3.066/10× 100 = 30.66 percentage