Question

10 g of CaCO3 contains....
(a) 10 mole of CaCO3
(c) 6x1022 atoms of Ca
(b) 1 g atom of
(d) 0.1 g equiv
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Answer 1

Answer:

The correct option is (c).

Explanation:

Mass of calcium carbonate = 10 g

Molar mass of calcium carbonate = 100 g/mol

Moles of calcium carbonate = $\frac{10 g}{100 g/mol}=0.1 mol$

1 mole of calcium carbonate contains 1 mole of calcium atom , 1 mole of carbon atoms  and 3 moles of oxygen atoms.

1 mole = $N_A=6.022\times 10^{23}$ atoms

1 mole of calcium = $1\times 6.022\times 10^{23}$ atoms of calcium.

Answer 2

Explanation:

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