Question

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Volume of gaseous product after reaction (1) 1 x 22.4 L (2) 2 x 22.4 L (3) 3 x 22.4 L (4) 4 x 22.4 L​

Answer 1

Answer:

4) 4 x 22.4 L

Explanation:

2H2 + O2 -> 2h20

4gm of hydrogen and 32 gm of oxygen combine to form water , i.e , 1:8 10 gm of hydrogen and 64 gm of oxygen combine to form water, then 2gm of hydrogen is left unreacted.

Therefore, Volme of gaseous product after reaction is 2gm Hydrogen that is, 1Mole of Hydrogen at STP = 22.4 L

Hence, option 4 is correct.

hope this helped you.