10 g of ice at 0°C is kept in a calorimeter of water equivalent 10 g at 0°C. How much heat should be supplied to the system to evaporate the water?
( Lf = 80 cal/gm, Lv = 540 cal/gm, Sw = 1 cal/gm)
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10(80) + (10+10)(1)(100)+ 10(540)
= 800 + 2000 + 5400
= 8200J
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