10 g of ice at 0°C is mixed with 10g of water of 60°C. the resultant temperature of the mixer is consider
the heat transfer between these two systems only ) [
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The latent heat required to melt all of the ice to liquid water at 0 C is 10 x 80 cal. The heat lost by the water starting at 10 C and reducing to zero degrees Celsius is 10 x 10 cal.
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The latent heat required to melt all of the ice of liquid water 0 C is 10*80 cal.The heat lost via water starting at 10 C and reducing to 0 degrees Celsius is 10*10 cal.
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