10 g of mno2 on reaction with HCl forms 22.4 l of cl2 at NTP ,the percentage impurity of mno2 is
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0% impurity . 10 g - 22.4L. then. 87g - ? ,. = 194.88 L. To check impurity , now compare the above data. , by cross multiply. I.e 10 × 194.88 = 1948.8 ,. there is no impurity ,. (if there is impurity then . eg: 10 = 20 , 1 = 2 , not possible , we should take 2/1 and then compare with given mass ie 10 , therefore 10- 2 = 8 , so 8% impurity will ) good luck If you like then press thank you and follow me
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