Question

10 g of NaOH is dissolved in 90 g of water calculate the mole fraction of both solute and solvent

Answer 1

Given:

10 g of NaOH is dissolved in 90 g of water.

To find:

Mole fraction of mole solute and solvent ?

Calculation:

• Moles of NaOH = 10/40 = 0.25 mol.

• Moles of Water = 90/18 = 5 mol.

Now, mole fraction of NaOH:

$\boxed{ \chi_{NaOH} = \dfrac{0.25}{0.25 + 5} = 0.047}$

Now, mole fraction of water:

$\boxed{ \chi_{H_{2}O} = \dfrac{5}{0.25 + 5} = 0.952}$

Hope It Helps.

Answer 2

Answer:

Mole fraction of Solute(NaOH) = 0.047

Mole fraction of Solvent(H2O) = 0.95

Explanation:

40g of NaOH = 1 mole

10g of NaOH = 10/40 mole = 0.25 moles

18g of H2O = 1 mole

90g of H2O = 90/18 = 5 moles

Mole fraction of solute = No. of moles of solute/Total no. of moles in soln,

Mole fraction of Solute(NaOH) = 0.25/5+0.25 = 0.25/5.25 = 1/21 = 0.047

Mole fraction of Solvent(H2O) = No. of Moles of Solvent/No. of moles in soln.

Mole fraction of Solvent(H2O)  = 5/0.25+5 = 5/5.25 = 1/1.05 = 0.95