Question

10 g of urea is present in 250 mL of aqueous solution at 27°C. The osmotic pressure of the solution is
a. 8.2 atm
b. 12.4 atm
c. 16.4 atm
d. 10.5 atm​

Answer 1

Given:

10 g of urea is present in 250 mL of aqueous solution at 27°C.

To find:

Osmotic pressure ?

Calculation:

General expression for OSMOTIC PRESSURE is:

$\rm\pi = C \times R \times T$

• 'C' is concentration, 'R' is Gas constant, 'T' is temperature.

$\rm \implies\pi = \dfrac{moles}{volume} \times R \times T$

$\rm \implies\pi = \dfrac{ \frac{10}{60} }{0.25} \times 0.082\times (27 + 273)$

$\rm \implies\pi = \dfrac{ \frac{10}{60} }{0.25} \times 0.082\times 300$

$\rm \implies\pi = 16.4 \: atm$

So, osmotic pressure is 16.4 atm.

Answer 2

Answer:

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