Question

10 g of water at 25°C was provided 50 calories of heat energy. The temperature of water increases by

Answer 1

Answer:

Specific heat of steam = 1 kilo cal kg - 1 °C - ! ... The heat energy required to raise the temperature of ... temperature of the mixture be t°C . Heat lost by water in calories = 300 x 1 x ( 25)

Answer 2

ANSWER ::

The temperature of water increases by 5°C

EXPLANATION ::

Let T be the final temperature

Niw

m = mass= 10

s-specific heat capacity

∆t = Change in temperature = T - 25

We know that

Q=ms∆t

50 =10×1×(T -25)

T-25 = 5

T = 30

So Final temperature = 30°C

So The temperature of water increases by

= 30°C - 25°C = 5°C